Q. Find the minimum value of the function f(x)=2x2−11.4x+21 to the nearest hundredth.Answer:
Find Vertex Form: To find the minimum value of the quadratic function f(x)=2x2−11.4x+21, we need to find the vertex of the parabola. The vertex form of a quadratic function is f(x)=a(x−h)2+k, where (h,k) is the vertex of the parabola. Since the coefficient of x2 is positive, the parabola opens upwards, and the vertex represents the minimum point.
Calculate x-coordinate: The x-coordinate of the vertex h can be found using the formula h=−2ab, where a is the coefficient of x2 and b is the coefficient of x in the standard form of the quadratic function. For the given function, a=2 and b=−11.4.
Calculate y-coordinate: Let's calculate the x-coordinate of the vertex:h=−(−11.4)/(2×2)=11.4/4=2.85
Substitute into Function: Now that we have the x-coordinate of the vertex, we can find the y-coordinate (k) by substituting h back into the original function:f(2.85)=2(2.85)2−11.4(2.85)+21
Calculate Minimum Value: Let's perform the calculation:f(2.85)=2(8.1225)−32.49+21f(2.85)=16.245−32.49+21f(2.85)=−16.245+21f(2.85)=4.755
Calculate Minimum Value: Let's perform the calculation:f(2.85)=2(8.1225)−32.49+21f(2.85)=16.245−32.49+21f(2.85)=−16.245+21f(2.85)=4.755The minimum value of the function to the nearest hundredth is therefore 4.76, as we round 4.755 to the nearest hundredth.
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