Q. Find the minimum value of the function f(x)=0.7x2+8x+25 to the nearest hundredth.Answer:
Calculate Vertex: To find the minimum value of the quadratic function f(x)=0.7x2+8x+25, we can use the vertex formula. The vertex of a parabola given by f(x)=ax2+bx+c is at the point (h,k), where h=−2ab and k is the value of the function at x=h.
Calculate x-coordinate: First, we calculate the x-coordinate of the vertex, h, using the formula h=−2ab. Here, a=0.7 and b=8.h=−2×0.78=−1.48=−5.71428571…
Round x-coordinate: Now we round h to the nearest hundredth to get h≈−5.71.
Calculate y-coordinate: Next, we calculate the y-coordinate of the vertex, k, by substituting h back into the function f(x).k=f(−5.71)=0.7(−5.71)2+8(−5.71)+25
Perform Calculations: Perform the calculations:k=0.7×32.6041+8×−5.71+25k=22.82287−45.68+25k=−0.85713
Round y-coordinate: Now we round k to the nearest hundredth to get k≈−0.86.
More problems from Find trigonometric functions using a calculator