Q. Find the maximum value of the function f(x)=−1.7x2+5x−0.9 to the nearest hundredth.Answer:
Find Vertex: To find the maximum value of the quadratic function f(x)=−1.7x2+5x−0.9, we need to find the vertex of the parabola. Since the coefficient of x2 is negative, the parabola opens downwards, and the vertex will give us the maximum value. The x-coordinate of the vertex can be found using the formula −2ab, where a is the coefficient of x2 and b is the coefficient of x.
Calculate x-coordinate: First, we calculate the x-coordinate of the vertex using the formula −2ab. Here, a=−1.7 and b=5. x-coordinate of the vertex = −2ab = −2×−1.75 = −−3.45 = 1.47058823529...
Round x-coordinate: Now we round the x-coordinate to the nearest hundredth. x-coordinate of the vertex ≈1.47
Substitute x into function: Next, we substitute x=1.47 into the function to find the y-coordinate of the vertex, which will give us the maximum value of the function.f(1.47)=−1.7(1.47)2+5(1.47)−0.9
Calculate y-coordinate: We perform the calculations:f(1.47)=−1.7(2.1609)+7.35−0.9f(1.47)=−3.67353+7.35−0.9f(1.47)=3.67647−0.9f(1.47)=2.77647
Round maximum value: Finally, we round the maximum value to the nearest hundredth.Maximum value of f(x)≈2.78
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