Q. Find the maximum value of the function f(x)=−0.6x2+3.5x−13 to the nearest hundredth.Answer:
Find Vertex: To find the maximum value of the quadratic function f(x)=−0.6x2+3.5x−13, we need to find the vertex of the parabola. Since the coefficient of x2 is negative, the parabola opens downwards, and the vertex will give us the maximum value. The x-coordinate of the vertex can be found using the formula −2ab, where a is the coefficient of x2 and b is the coefficient of x.
Calculate x-coordinate: First, we calculate the x-coordinate of the vertex using the formula −2ab. Here, a=−0.6 and b=3.5. x-coordinate of vertex = −2ab = −2×−0.63.5 = −−1.23.5 = 2.916666...
Round x-coordinate: Now, we round the x-coordinate to the nearest hundredth, which gives us 2.92.
Find y-coordinate: Next, we need to find the y-coordinate of the vertex by substituting x=2.92 into the function f(x).f(2.92)=−0.6(2.92)2+3.5(2.92)−13
Perform calculations: We perform the calculations:f(2.92)=−0.6(8.5264)+10.22−13f(2.92)=−5.11584+10.22−13f(2.92)=5.10416−13f(2.92)=−7.89584
Round y-coordinate: Finally, we round the y-coordinate to the nearest hundredth to find the maximum value of the function.Maximum value of f(x)≈−7.90
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