Find the line's slope and a point on the line. y+1=(2)/(3)(x-1)

Rewrite Equation: Rewrite the equation in slope-intercept form (y = mx + b) to identify the slope and y-intercept. y + 1 = (2/3)(x - 1) y = (2/3)x - (2/3) - 1 y = (2/3)x - (2/3) - (3/3) y = (2/3)x - (5/3) Identify Slope: Identify the slope (m) from the equation y = (2/3)x - (5/3). Slope, m = 2/3 Find Point on Line: Identify a point on the line using the y-intercept found in the equation. The y-intercept is at y = -5/3, which corresponds to the point (0, -5/3) on the y-axis.

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Algebra 2

Factor sums and differences of cubes

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Q. Find the line's slope and a point on the line.

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y+1=\frac{2}{3}(x-1)

Rewrite Equation: Rewrite the equation in slope-intercept form $y = mx + b$ to identify the slope and y-intercept. $\newline$ $y + 1 = \left(\frac{2}{3}\right)(x - 1)$ $\newline$ $y = \left(\frac{2}{3}\right)x - \left(\frac{2}{3}\right) - 1$ $\newline$ $y = \left(\frac{2}{3}\right)x - \left(\frac{2}{3}\right) - \left(\frac{3}{3}\right)$ $\newline$ $y = \left(\frac{2}{3}\right)x - \left(\frac{5}{3}\right)$
Identify Slope: Identify the slope $m$ from the equation $y = \frac{2}{3}x - \frac{5}{3}$ . $\newline$ Slope, $m = \frac{2}{3}$
Find Point on Line: Identify a point on the line using the y-intercept found in the equation. $\newline$ The y-intercept is at $y = -\frac{5}{3}$ , which corresponds to the point $(0, -\frac{5}{3})$ on the y-axis.