Find the line's slope and a point on the line. y-1=-(1)/(3)(x+5)

Rewrite equation: Rewrite the equation in slope-intercept form (y = mx + b) to identify the slope and y-intercept. y - 1 = -(1/3)(x + 5) y = -(1/3)x - (1/3)(5) + 1 y = -(1/3)x - 5/3 + 1 y = -(1/3)x - 2/3 Identify slope: Identify the slope (m) from the equation y = mx + b. Slope (m) = -1/3 Identify point: Identify a point on the line using the y-intercept (b). The y-intercept is at y = -2/3 when x = 0. So, the point (0, -2/3) is on the line.

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Find the line's slope and a point on the line.

y-1=-(1)/(3)(x+5)

Find the line's slope and a point on the line. $\newline$ $y-1=-\frac{1}{3}(x+5)$

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Q. Find the line's slope and a point on the line.

\newline

y-1=-\frac{1}{3}(x+5)

Rewrite equation: Rewrite the equation in slope-intercept form $y = mx + b$ to identify the slope and y-intercept. $\newline$ $y - 1 = -\left(\frac{1}{3}\right)(x + 5)$ $\newline$ $y = -\left(\frac{1}{3}\right)x - \left(\frac{1}{3}\right)(5) + 1$ $\newline$ $y = -\left(\frac{1}{3}\right)x - \frac{5}{3} + 1$ $\newline$ $y = -\left(\frac{1}{3}\right)x - \frac{2}{3}$
Identify slope: Identify the slope $m$ from the equation $y = mx + b$ . $\newline$ Slope $m$ = $-\frac{1}{3}$
Identify point: Identify a point on the line using the y-intercept ( extit{b}). $\newline$ The y-intercept is at $y = -\frac{2}{3}$ when $x = 0$ . $\newline$ So, the point $(0, -\frac{2}{3})$ is on the line.