Find the inverse function of the function f(x)=(1)/(5)x+9. f^(-1)(x)=5x-9 f^(-1)(x)=5x-45 f^(-1)(x)=(1)/(5)x-9 f^(-1)(x)=(1)/(5)x-45

Replace f(x) with y: To find the inverse function, we first replace f(x) with y for simplicity. y = (1/5)x + 9Swap x and y: Next, we swap x and y to find the inverse function. x = (1/5)y + 9Solve for y: Now, we solve for y. Subtract 9 from both sides to isolate the term with y on one side. x - 9 = (1/5)yMultiply by 5: Multiply both sides by 5 to solve for y. 5(x - 9) = yDistribute the 5: Distribute the 5 on the left side of the equation. 5x - 45 = yReplace y with f^(-1)(x): Replace y with f^(-1)(x) to denote the inverse function. f^(-1)(x) = 5x - 45

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Find the inverse function of the function
f(x)=(1)/(5)x+9.

f^(-1)(x)=5x-9

f^(-1)(x)=5x-45

f^(-1)(x)=(1)/(5)x-9

f^(-1)(x)=(1)/(5)x-45

Find the inverse function of the function $f(x)=\frac{1}{5} x+9$ . $\newline$ $f^{-1}(x)=5 x-9$ $\newline$ $f^{-1}(x)=5 x-45$ $\newline$ $f^{-1}(x)=\frac{1}{5} x-9$ $\newline$ $f^{-1}(x)=\frac{1}{5} x-45$

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Math Problems

Algebra 2

Find the vertex of the transformed function

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Q. Find the inverse function of the function

f(x)=\frac{1}{5} x+9

\newline

f^{-1}(x)=5 x-9

\newline

f^{-1}(x)=5 x-45

\newline

f^{-1}(x)=\frac{1}{5} x-9

\newline

f^{-1}(x)=\frac{1}{5} x-45

Replace $f(x)$ with $y$ : To find the inverse function, we first replace $f(x)$ with $y$ for simplicity. $\newline$ $y = \frac{1}{5}x + 9$
Swap x and y: Next, we swap x and y to find the inverse function. $x = \frac{1}{5}y + 9$
Solve for y: Now, we solve for y. Subtract $9$ from both sides to isolate the term with $y$ on one side. $\newline$ $x - $9$ = \left(\frac{$1$}{$5$}\right)y
Multiply by $5$: Multiply both sides by $5$ to solve for $y$.\[5(x - 9) = y\]
Distribute the $5$: Distribute the $5$ on the left side of the equation. $5x - 45 = y$
Replace $y$ with $f^{-1}(x)$: Replace $y$ with $f^{-1}(x)$ to denote the inverse function.$\newline$$f^{-1}(x) = 5x - 45$