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Find the inverse function in slope-intercept form 
(mx+b) :

f(x)=-x-16
Answer: 
f^(-1)(x)=

Find the inverse function in slope-intercept form (mx+b) (\mathrm{mx}+\mathrm{b}) :\newlinef(x)=x16 f(x)=-x-16 \newlineAnswer: f1(x)= f^{-1}(x)=

Full solution

Q. Find the inverse function in slope-intercept form (mx+b) (\mathrm{mx}+\mathrm{b}) :\newlinef(x)=x16 f(x)=-x-16 \newlineAnswer: f1(x)= f^{-1}(x)=
  1. Write function as yy: To find the inverse function, we first write the function as y=x16y = -x - 16.
  2. Swap xx and yy: Next, we swap xx and yy to find the inverse. This gives us x=y16x = -y - 16.
  3. Isolate y term: Now, we solve for y. We start by adding 1616 to both sides to isolate the term with y. This gives us x+16=yx + 16 = -y.
  4. Multiply by 1-1: To solve for yy, we multiply both sides by 1-1 to get yy by itself. This gives us x16=y-x - 16 = y.
  5. Inverse function in slope-intercept form: We now have the inverse function in slope-intercept form, which is y=x16y = -x - 16. However, since we are using the inverse notation, we write it as f1(x)=x16f^{-1}(x) = -x - 16.

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