Find the inverse function in slope-intercept form (mx+b) : f(x)=-3x+15 Answer: f^(-1)(x)=

Write function as equation: To find the inverse function, we first write the function as an equation with y instead of f(x): y = -3x + 15Swap x and y: Next, we swap x and y to find the inverse: x = -3y + 15Solve for y: Now, we solve for y to get it in slope-intercept form (y = mx + b): Add 3y to both sides: 3y = -x + 15Divide by 3: Divide both sides by 3 to solve for y: y = (-1/3)x + 5Inverse function in slope-intercept form: The inverse function in slope-intercept form is: f^(-1)(x) = (-1/3)x + 5

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Find the inverse function in slope-intercept form
(mx+b) :

f(x)=-3x+15
Answer:
f^(-1)(x)=

Find the inverse function in slope-intercept form $(\mathrm{mx}+\mathrm{b})$ : $\newline$ $f(x)=-3 x+15$ $\newline$ Answer: $f^{-1}(x)=$

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Algebra 2

Find the vertex of the transformed function

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Q. Find the inverse function in slope-intercept form

(\mathrm{mx}+\mathrm{b})

\newline

f(x)=-3 x+15

\newline

Answer:

f^{-1}(x)=

Write function as equation: To find the inverse function, we first write the function as an equation with $y$ instead of $f(x)$ : $y = -3x + 15$
Swap x and y: Next, we swap x and y to find the inverse: $x = -3y + 15$
Solve for y: Now, we solve for y to get it in slope-intercept form $y = mx + b$ : $\newline$ Add $3y$ to both sides: $\newline$ $3y = -x + 15$
Divide by $3$ : Divide both sides by $3$ to solve for $y$ : $y = \left(-\frac{1}{3}\right)x + 5$
Inverse function in slope-intercept form: The inverse function in slope-intercept form is: $f^{-1}(x) = \left(-\frac{1}{3}\right)x + 5$