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Find the inverse function in slope-intercept form 
(mx+b) :

f(x)=2x+2
Answer: 
f^(-1)(x)=

Find the inverse function in slope-intercept form (mx+b) (\mathrm{mx}+\mathrm{b}) :\newlinef(x)=2x+2 f(x)=2 x+2 \newlineAnswer: f1(x)= f^{-1}(x)=

Full solution

Q. Find the inverse function in slope-intercept form (mx+b) (\mathrm{mx}+\mathrm{b}) :\newlinef(x)=2x+2 f(x)=2 x+2 \newlineAnswer: f1(x)= f^{-1}(x)=
  1. Write function as y=2x+2y = 2x + 2: To find the inverse function, we first write the function as y=2x+2y = 2x + 2, where yy is the output and xx is the input.
  2. Swap xx and yy: Next, we swap the roles of xx and yy to find the inverse. This means we replace yy with xx and xx with yy, giving us x=2y+2x = 2y + 2.
  3. Solve for y: Now, we need to solve for yy to get the inverse function in slope-intercept form (y=mx+by = mx + b). Subtract 22 from both sides to isolate the term with yy on one side: x2=2yx - 2 = 2y.
  4. Divide by 22: Divide both sides by 22 to solve for y: (x2)/2=y(x - 2) / 2 = y.
  5. Simplify to slope-intercept form: Simplify the equation to get the inverse function in slope-intercept form: y=12x1y = \frac{1}{2}x - 1.

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