Find the inverse function in slope-intercept form (mx+b) : f(x)=-(1)/(2)x-7 Answer: f^(-1)(x)=

Replace with y: To find the inverse function, we first replace f(x) with y for simplicity: y = -(1/2)x - 7Swap x and y: Next, we swap x and y to find the inverse function: x = -(1/2)y - 7Solve for y: Now, we solve for y to get it in the form y = mx + b, which is the slope-intercept form. First, we add 7 to both sides of the equation: x + 7 = -(1/2)yAdd 7: Then, we multiply both sides by -2 to solve for y: -2(x + 7) = yMultiply by -2: Distribute the -2 on the left side of the equation: -2x - 14 = yDistribute -2: Finally, we write the inverse function with y on the left side: f^(-1)(x) = -2x - 14

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Find the inverse function in slope-intercept form
(mx+b) :

f(x)=-(1)/(2)x-7
Answer:
f^(-1)(x)=

Find the inverse function in slope-intercept form $(\mathrm{mx}+\mathrm{b})$ : $\newline$ $f(x)=-\frac{1}{2} x-7$ $\newline$ Answer: $f^{-1}(x)=$

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Algebra 2

Find the vertex of the transformed function

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Q. Find the inverse function in slope-intercept form

(\mathrm{mx}+\mathrm{b})

\newline

f(x)=-\frac{1}{2} x-7

\newline

Answer:

f^{-1}(x)=

Replace with $y$ : To find the inverse function, we first replace $f(x)$ with $y$ for simplicity: $\newline$ $y = -\frac{1}{2}x - 7$
Swap x and y: Next, we swap x and y to find the inverse function: $\newline$ $x = -\frac{1}{2}y - 7$
Solve for y: Now, we solve for $y$ to get it in the form $y = mx + b$ , which is the slope-intercept form. First, we add $7$ to both sides of the equation: $\newline$ $x + 7 = -\left(\frac{1}{2}\right)y$
Add $7$ : Then, we multiply both sides by $-2$ to solve for $y$ : $-2(x + 7) = y$
Multiply by $-2$ : Distribute the $-2$ on the left side of the equation: $\newline$ $-2x - 14 = y$
Distribute $-2$ : Finally, we write the inverse function with $y$ on the left side: $\newline$ $f^{(-1)}(x) = -2x - 14$