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Find the first 44 non-zero terms of the Taylor polynomial centered at x=0x=0 for f(x)=cos6xf(x)=\cos 6x.

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Q. Find the first 44 non-zero terms of the Taylor polynomial centered at x=0x=0 for f(x)=cos6xf(x)=\cos 6x.
  1. Find f(00): To find the Taylor polynomial of f(x) = cos(66x) centered at x = 00, we need to calculate the derivatives of f(x) at x = 00 and use the Taylor series formula:\newlineP(x)=f(0)+f(0)x+f(0)2!x2+f(0)3!x3+ P(x) = f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 + \frac{f(0)}{3!}x^3 + \ldots \newlineFirst, we find f(00):\newlinef(x)=cos(6x) f(x) = \cos(6x) \newlinef(0)=cos(60) f(0) = \cos(6 \cdot 0) \newlinef(0)=cos(0) f(0) = \cos(0) \newlinef(0)=1 f(0) = 1
  2. First Derivative: Next, we find the first derivative of f(x) and evaluate it at x = 00:\newlinef(x)=6sin(6x) f'(x) = -6\sin(6x) \newlinef(0)=6sin(60) f'(0) = -6\sin(6 \cdot 0) \newlinef(0)=6sin(0) f'(0) = -6\sin(0) \newlinef(0)=0 f'(0) = 0 \newlineSince the first derivative at x = 00 is zero, it does not contribute to the non-zero terms of the Taylor polynomial.
  3. Second Derivative: Now, we find the second derivative of f(x) and evaluate it at x = 00:\newlinef(x)=36cos(6x) f''(x) = -36\cos(6x) \newlinef(0)=36cos(60) f''(0) = -36\cos(6 \cdot 0) \newlinef(0)=36cos(0) f''(0) = -36\cos(0) \newlinef(0)=36 f''(0) = -36 \newlineThe second derivative at x = 00 is non-zero and contributes to the Taylor polynomial.
  4. Third Derivative: Next, we find the third derivative of f(x) and evaluate it at x = 00:\newlinef(x)=216sin(6x) f(x) = 216\sin(6x) \newlinef(0)=216sin(60) f(0) = 216\sin(6 \cdot 0) \newlinef(0)=216sin(0) f(0) = 216\sin(0) \newlinef(0)=0 f(0) = 0 \newlineSince the third derivative at x = 00 is zero, it does not contribute to the non-zero terms of the Taylor polynomial.
  5. Fourth Derivative: Finally, we find the fourth derivative of f(x) and evaluate it at x = 00:\newlinef(x)=1296cos(6x) f'(x) = 1296\cos(6x) \newlinef(0)=1296cos(60) f'(0) = 1296\cos(6 \cdot 0) \newlinef(0)=1296cos(0) f'(0) = 1296\cos(0) \newlinef(0)=1296 f'(0) = 1296 \newlineThe fourth derivative at x = 00 is non-zero and contributes to the Taylor polynomial.
  6. Write Taylor Polynomial: Now we can write the first 44 non-zero terms of the Taylor polynomial for f(x) = cos(66x) centered at x = 00:\newlineP(x)=f(0)+f(0)2!x2+f(0)4!x4 P(x) = f(0) + \frac{f''(0)}{2!}x^2 + \frac{f'(0)}{4!}x^4 \newlineP(x)=1362!x2+12964!x4 P(x) = 1 - \frac{36}{2!}x^2 + \frac{1296}{4!}x^4 \newlineP(x)=118x2+129624x4 P(x) = 1 - 18x^2 + \frac{1296}{24}x^4 \newlineP(x)=118x2+54x4 P(x) = 1 - 18x^2 + 54x^4

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