Q. Find the first 4 non-zero terms of the Taylor polynomial centered at x=0 for f(x)=cos6x.
Find f(0): To find the Taylor polynomial of f(x) = cos(6x) centered at x = 0, we need to calculate the derivatives of f(x) at x = 0 and use the Taylor series formula:P(x)=f(0)+f′(0)x+2!f′′(0)x2+3!f(0)x3+…First, we find f(0):f(x)=cos(6x)f(0)=cos(6⋅0)f(0)=cos(0)f(0)=1
First Derivative: Next, we find the first derivative of f(x) and evaluate it at x = 0:f′(x)=−6sin(6x)f′(0)=−6sin(6⋅0)f′(0)=−6sin(0)f′(0)=0Since the first derivative at x = 0 is zero, it does not contribute to the non-zero terms of the Taylor polynomial.
Second Derivative: Now, we find the second derivative of f(x) and evaluate it at x = 0:f′′(x)=−36cos(6x)f′′(0)=−36cos(6⋅0)f′′(0)=−36cos(0)f′′(0)=−36The second derivative at x = 0 is non-zero and contributes to the Taylor polynomial.
Third Derivative: Next, we find the third derivative of f(x) and evaluate it at x = 0:f(x)=216sin(6x)f(0)=216sin(6⋅0)f(0)=216sin(0)f(0)=0Since the third derivative at x = 0 is zero, it does not contribute to the non-zero terms of the Taylor polynomial.
Fourth Derivative: Finally, we find the fourth derivative of f(x) and evaluate it at x = 0:f′(x)=1296cos(6x)f′(0)=1296cos(6⋅0)f′(0)=1296cos(0)f′(0)=1296The fourth derivative at x = 0 is non-zero and contributes to the Taylor polynomial.
Write Taylor Polynomial: Now we can write the first 4 non-zero terms of the Taylor polynomial for f(x) = cos(6x) centered at x = 0:P(x)=f(0)+2!f′′(0)x2+4!f′(0)x4P(x)=1−2!36x2+4!1296x4P(x)=1−18x2+241296x4P(x)=1−18x2+54x4
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