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Find the equation of the axis of symmetry for the parabola y=x2+2xy = x^2 + 2x. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline_____\_\_\_\_\_

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Q. Find the equation of the axis of symmetry for the parabola y=x2+2xy = x^2 + 2x. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline_____\_\_\_\_\_
  1. Identify values of aa and bb: First, identify the values of aa and bb in the equation y=x2+2xy = x^2 + 2x. The standard form of a quadratic equation is y=ax2+bx+cy = ax^2 + bx + c. By comparing, we can see that a=1a = 1 and b=2b = 2.
  2. Substitute values into formula: Now, substitute the values of aa and bb into the formula for the axis of symmetry, x=−b2ax = -\frac{b}{2a}. This gives us x=−22⋅1x = -\frac{2}{2\cdot 1}.
  3. Perform calculation: Perform the calculation: x=−2/(2⋅1)x = -2/(2\cdot1) simplifies to x=−2/2x = -2/2, which further simplifies to x=−1x = -1.
  4. Equation of axis of symmetry: The equation of the axis of symmetry for the parabola y=x2+2xy = x^2 + 2x is therefore x=−1x = -1.

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