Find the equation of the axis of symmetry for the parabola y = x^2 + 6x + 9 . Simplify any numbers and write them as proper fractions, improper fractions, or integers. _____

Find Axis of Symmetry: The axis of symmetry for a parabola given by the equation y = ax^2 + bx + c is found using the formula x = -b/(2a). We substitute the values of a and b into this formula to find the axis of symmetry. x = -b/(2a) = -6/(2*1) = -6/2 = -3Calculate x Value: The equation of the axis of symmetry is therefore x = -3. This is a vertical line that passes through the vertex of the parabola and divides it into two symmetrical halves.

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Find the equation of the axis of symmetry for the parabola $y = x^2 + 6x + 9$ . $\newline$ Simplify any numbers and write them as proper fractions, improper fractions, or integers. $\newline$ $\_\_\_\_\_$

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Algebra 2

Characteristics of quadratic functions: equations

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Q. Find the equation of the axis of symmetry for the parabola

y = x^2 + 6x + 9

\newline

Simplify any numbers and write them as proper fractions, improper fractions, or integers.

\newline

\_\_\_\_\_

Find Axis of Symmetry: The axis of symmetry for a parabola given by the equation $y = ax^2 + bx + c$ is found using the formula $x = -\frac{b}{2a}$ . We substitute the values of $a$ and $b$ into this formula to find the axis of symmetry. $x = -\frac{b}{2a} = -\frac{6}{2\cdot 1} = -\frac{6}{2} = -3$
Calculate $x$ Value: The equation of the axis of symmetry is therefore $x = -3$ . This is a vertical line that passes through the vertex of the parabola and divides it into two symmetrical halves.