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Find the equation of the axis of symmetry for the parabola y=x2+x+152y = x^2 + x + \frac{15}{2}. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline_____

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Q. Find the equation of the axis of symmetry for the parabola y=x2+x+152y = x^2 + x + \frac{15}{2}. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline_____
  1. Identify Coefficients: Identify the coefficients of the quadratic equation.\newlineThe quadratic equation is given in the form y=ax2+bx+cy = ax^2 + bx + c. For the parabola y=x2+x+152y = x^2 + x + \frac{15}{2}, we can identify the coefficients as follows:\newlinea=1a = 1 (coefficient of x2x^2)\newlineb=1b = 1 (coefficient of xx)\newlinec=152c = \frac{15}{2} (constant term)
  2. Use Axis of Symmetry Formula: Use the formula for the axis of symmetry.\newlineThe axis of symmetry for a parabola in the form y=ax2+bx+cy = ax^2 + bx + c is given by the formula x=b2ax = -\frac{b}{2a}. We will substitute the values of aa and bb into this formula to find the axis of symmetry.
  3. Substitute Values into Formula: Substitute the values of aa and bb into the formula.a=1a = 1b=1b = 1x=b2a=121=12x = -\frac{b}{2a} = -\frac{1}{2\cdot 1} = -\frac{1}{2}
  4. Write Axis of Symmetry Equation: Write the equation of the axis of symmetry.\newlineThe axis of symmetry is a vertical line, so its equation is of the form x=constantx = \text{constant}. In this case, the constant is 12-\frac{1}{2}. Therefore, the equation of the axis of symmetry is x=12x = -\frac{1}{2}.

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