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Find the equation of the axis of symmetry for the parabola y=x22x310y = x^2 - 2x - \frac{3}{10}. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline__\_\_

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Q. Find the equation of the axis of symmetry for the parabola y=x22x310y = x^2 - 2x - \frac{3}{10}. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline__\_\_
  1. Identify Coefficients: Identify the coefficients of the quadratic equation.\newlineThe given quadratic equation is y=x22x310y = x^2 - 2x - \frac{3}{10}. We can compare this with the standard form of a quadratic equation, which is y=ax2+bx+cy = ax^2 + bx + c, to find the values of aa, bb, and cc.\newlineHere, a=1a = 1, b=2b = -2, and c=310c = -\frac{3}{10}.
  2. Use Axis of Symmetry Formula: Use the formula for the axis of symmetry.\newlineThe axis of symmetry for a parabola given by y=ax2+bx+cy = ax^2 + bx + c is x=b2ax = -\frac{b}{2a}. We will substitute the values of aa and bb into this formula to find the axis of symmetry.
  3. Calculate Axis of Symmetry: Calculate the axis of symmetry.\newlineSubstitute a=1a = 1 and b=2b = -2 into the formula x=b2ax = -\frac{b}{2a}.\newlinex=(2)/(21)x = -(-2)/(2\cdot 1)\newlinex=22x = \frac{2}{2}\newlinex=1x = 1\newlineThe axis of symmetry is the line x=1x = 1.

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