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Find the equation of the axis of symmetry for the parabola y=x2+3x5y = x^2 + 3x - 5. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline_____\_\_\_\_\_

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Q. Find the equation of the axis of symmetry for the parabola y=x2+3x5y = x^2 + 3x - 5. \newlineSimplify any numbers and write them as proper fractions, improper fractions, or integers.\newline_____\_\_\_\_\_
  1. Identify coefficients: Identify the coefficients aa, bb, and cc in the quadratic equation y=ax2+bx+cy = ax^2 + bx + c. The given equation is y=x2+3x5y = x^2 + 3x - 5. Here, a=1a = 1, b=3b = 3, and c=5c = -5.
  2. Use axis of symmetry formula: Use the formula for the axis of symmetry, which is x=b2ax = -\frac{b}{2a}.\newlineSubstitute the values of aa and bb into the formula.\newlinex=321x = -\frac{3}{2\cdot 1}
  3. Simplify expression: Simplify the expression to find the value of xx.x=32x = -\frac{3}{2}This is the equation of the axis of symmetry for the given parabola.

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