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Find the discriminant.\newlinev2+v+5=0v^2 + v + 5 = 0

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Q. Find the discriminant.\newlinev2+v+5=0v^2 + v + 5 = 0
  1. Identify coefficients: Identify the coefficients of the quadratic equation.\newlineThe quadratic equation is in the form av2+bv+c=0a v^2 + b v + c = 0. For the equation v2+v+5=0v^2 + v + 5 = 0, the coefficients are:\newlinea = 11 (coefficient of v2v^2)\newlineb = 11 (coefficient of vv)\newlinec = 55 (constant term)
  2. Calculate discriminant: Calculate the discriminant using the formula D=b24acD = b^2 - 4ac. Substitute the identified values into the discriminant formula: D=(1)24×1×5D = (1)^2 - 4 \times 1 \times 5
  3. Perform calculation: Perform the calculation to find the value of the discriminant.\newlineD=14×5D = 1 - 4 \times 5\newlineD=120D = 1 - 20\newlineD=19D = -19

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