Find the discriminant. t^2 + 6t - 1 = 0 ____

Identify values: Identify the values of a, b, and c by comparing the given equation t^2 + 6t - 1 = 0 with the standard quadratic equation form ax^2 + bx + c = 0. Here, a = 1, b = 6, and c = -1.Calculate discriminant: Use the discriminant formula D = b^2 - 4ac to calculate the discriminant of the quadratic equation. Substitute 1 for a, 6 for b, and -1 for c into the formula. D = (6)^2 - 4 * 1 * (-1)Find value of discriminant: Perform the calculations to find the value of the discriminant. D = 36 - 4 * 1 * (-1) D = 36 + 4 D = 40

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Find the discriminant. $\newline$ $t^2 + 6t - 1 = 0$

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Algebra 1

Using the discriminant

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Q. Find the discriminant.

\newline

t^2 + 6t - 1 = 0

Identify values: Identify the values of $a$ , $b$ , and $c$ by comparing the given equation $t^2 + 6t - 1 = 0$ with the standard quadratic equation form $ax^2 + bx + c = 0$ . Here, $a = 1$ , $b = 6$ , and $c = -1$ .
Calculate discriminant: Use the discriminant formula $D = b^2 - 4ac$ to calculate the discriminant of the quadratic equation. $\newline$ Substitute $1$ for $a$ , $6$ for $b$ , and $-1$ for $c$ into the formula. $\newline$ $D = (6)^2 - 4 \times 1 \times (-1)$
Find value of discriminant: Perform the calculations to find the value of the discriminant. $\newline$ $D = 36 - 4 \times 1 \times (-1)$ $\newline$ $D = 36 + 4$ $\newline$ $D = 40$