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Find the discriminant.\newlines2+5s+1=0s^2 + 5s + 1 = 0

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Q. Find the discriminant.\newlines2+5s+1=0s^2 + 5s + 1 = 0
  1. Identify coefficients: Identify the coefficients aa, bb, and cc from the quadratic equation s2+5s+1=0s^2 + 5s + 1 = 0 by comparing it to the standard form ax2+bx+c=0ax^2 + bx + c = 0. Here, a=1a = 1, b=5b = 5, and c=1c = 1.
  2. Calculate discriminant: Use the discriminant formula D=b24acD = b^2 - 4ac to calculate the discriminant of the quadratic equation.\newlineSubstitute the identified values into the formula: D=(5)24×1×1D = (5)^2 - 4 \times 1 \times 1.
  3. Perform calculation: Perform the calculation to find the discriminant.\newlineD=254×1×1D = 25 - 4 \times 1 \times 1\newlineD=254D = 25 - 4\newlineD=21D = 21

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