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Find the discriminant.\newline9t2+6t+1=09t^2 + 6t + 1 = 0

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Full solution

Q. Find the discriminant.\newline9t2+6t+1=09t^2 + 6t + 1 = 0
  1. Identify values: Identify the values of aa, bb, and cc from the quadratic equation in the form at2+bt+c=0at^2 + bt + c = 0. Comparing 9t2+6t+1=09t^2 + 6t + 1 = 0 with at2+bt+c=0at^2 + bt + c = 0, we find: a=9a = 9 b=6b = 6 c=1c = 1
  2. Calculate discriminant: Use the discriminant formula D=b2−4acD = b^2 - 4ac to calculate the discriminant of the quadratic equation.\newlineSubstitute 99 for aa, 66 for bb, and 11 for cc in the formula.\newlineD=(6)2−4×9×1D = (6)^2 - 4 \times 9 \times 1
  3. Find value of discriminant: Perform the calculations to find the value of the discriminant.\newlineD=36−4×9×1D = 36 - 4 \times 9 \times 1\newlineD=36−36D = 36 - 36\newlineD=0D = 0

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