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Find the discriminant.\newline4t2+4t+1=04t^2 + 4t + 1 = 0

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Full solution

Q. Find the discriminant.\newline4t2+4t+1=04t^2 + 4t + 1 = 0
  1. Identify values: Identify the values of aa, bb, and cc from the quadratic equation in the form at2+bt+c=0at^2 + bt + c = 0. Comparing 4t2+4t+1=04t^2 + 4t + 1 = 0 with at2+bt+c=0at^2 + bt + c = 0, we find: a=4a = 4 b=4b = 4 c=1c = 1
  2. Use discriminant formula: Use the discriminant formula D=b2−4acD = b^2 - 4ac to find the discriminant of the quadratic equation.\newlineSubstitute the identified values into the formula:\newlineD=(4)2−4×4×1D = (4)^2 - 4 \times 4 \times 1
  3. Calculate discriminant: Calculate the discriminant using the substituted values.\newlineD=16−4×4×1D = 16 - 4 \times 4 \times 1\newlineD=16−16D = 16 - 16\newlineD=0D = 0

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