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Find the discriminant.\newline3y2+8y+1=03y^2 + 8y + 1 = 0

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Full solution

Q. Find the discriminant.\newline3y2+8y+1=03y^2 + 8y + 1 = 0
  1. Identify values: Identify the values of aa, bb, and cc in the quadratic equation 3y2+8y+1=03y^2 + 8y + 1 = 0 by comparing it to the standard form ax2+bx+c=0ax^2 + bx + c = 0.\newlinea=3a = 3\newlineb=8b = 8\newlinec=1c = 1
  2. Calculate discriminant: Calculate the discriminant using the formula D=b2−4acD = b^2 - 4ac.\newlineSubstitute the identified values into the formula:\newlineD=82−4×3×1D = 8^2 - 4 \times 3 \times 1
  3. Perform calculations: Perform the calculations to find the value of the discriminant.\newlineD=64−4×3×1D = 64 - 4 \times 3 \times 1\newlineD=64−12D = 64 - 12\newlineD=52D = 52

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