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Find the discriminant.\newline3t2−2t−9=03t^2 - 2t - 9 = 0

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Full solution

Q. Find the discriminant.\newline3t2−2t−9=03t^2 - 2t - 9 = 0
  1. Identify values: Identify the values of aa, bb, and cc in the quadratic equation 3t2−2t−9=03t^2 - 2t - 9 = 0 by comparing it to the standard form ax2+bx+c=0ax^2 + bx + c = 0.\newlinea=3a = 3\newlineb=−2b = -2\newlinec=−9c = -9
  2. Calculate discriminant: Calculate the discriminant using the formula D=b2−4acD = b^2 - 4ac with the identified values of aa, bb, and cc.D=(−2)2−4×3×(−9)D = (-2)^2 - 4 \times 3 \times (-9)
  3. Simplify calculation: Simplify the discriminant calculation. \newlineD=4+108D = 4 + 108\newlineD=112D = 112

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