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Find the derivative of the function.\newlineg(t)=1(7t+1)6g(t)=\frac{1}{(7t+1)^{6}}

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Q. Find the derivative of the function.\newlineg(t)=1(7t+1)6g(t)=\frac{1}{(7t+1)^{6}}
  1. Identify function: Identify the function to differentiate.\newlineWe are given the function g(t)=1(7t+1)6g(t) = \frac{1}{(7t+1)^{6}}. We need to find its derivative with respect to tt.
  2. Apply chain rule: Apply the chain rule for differentiation.\newlineThe chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. In this case, the outer function is f(u)=u6f(u) = u^{-6} and the inner function is u(t)=7t+1u(t) = 7t + 1.
  3. Differentiate outer function: Differentiate the outer function with respect to the inner function.\newlineThe derivative of f(u)=u6f(u) = u^{-6} with respect to uu is f(u)=6u7f'(u) = -6u^{-7}.
  4. Differentiate inner function: Differentiate the inner function with respect to tt. The derivative of u(t)=7t+1u(t) = 7t + 1 with respect to tt is u(t)=7u'(t) = 7.
  5. Apply chain rule: Apply the chain rule by multiplying the derivatives from Step 33 and Step 44.\newlineThe derivative of g(t)g(t) with respect to tt is g(t)=f(u(t))u(t)=6(7t+1)77g'(t) = f'(u(t)) \cdot u'(t) = -6(7t + 1)^{-7} \cdot 7.
  6. Simplify expression: Simplify the expression.\newlineg(t)=6×7×(7t+1)7=42×(7t+1)7g'(t) = -6 \times 7 \times (7t + 1)^{-7} = -42 \times (7t + 1)^{-7}.

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