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Find the coordinates of the vertex of
y=3(x-1)^(2)+4

Find the coordinates of the vertex of $y=3(x-1)^{2}+4$

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Write a quadratic function from its x-intercepts and another point

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Q. Find the coordinates of the vertex of

y=3(x-1)^{2}+4

Identify Vertex Form: The vertex form of a parabola's equation is $y = a(x - h)^2 + k$ , where $(h, k)$ is the vertex of the parabola. In the given equation $y = 3(x - 1)^2 + 4$ , we can see that it is already in vertex form.
Find $h$ and $k$ : Identify the values of $h$ and $k$ from the equation. The value of $h$ is the $x$ -coordinate of the vertex, and the value of $k$ is the $y$ -coordinate of the vertex. In the given equation, $h = 1$ and $k = 4$ .
Calculate Vertex Coordinates: The coordinates of the vertex are therefore $(h, k) = (1, 4)$ .

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