Q. Find the coordinates of the vertex of the following parabola using graphing technology. Write your answer as an (x,y) point.y=3x2−12Answer:
Vertex Form Explanation: The vertex form of a parabola is y=a(x−h)2+k, where (h,k) is the vertex of the parabola. To find the vertex of the parabola given by y=3x2−12, we need to complete the square or use the vertex formula h=−2ab and k=c−4ab2 for the standard form y=ax2+bx+c. In this case, a=3, b=0, and c=−12. Since there is no b term, the vertex will be at (h,k)0. To find the (h,k)1-coordinate of the vertex, we substitute (h,k)2 into the equation y=3x2−12.
Calculate Vertex Coordinates: Substitute x=0 into the equation y=3x2−12 to find the y-coordinate of the vertex.y=3(0)2−12y=0−12y=−12So, the y-coordinate of the vertex is −12.
Final Vertex Coordinates: We have found the x-coordinate of the vertex to be 0 and the y-coordinate to be −12. Therefore, the coordinates of the vertex of the parabola y=3x2−12 are (0,−12).
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