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Find the coordinates of the vertex of the following parabola using graphing technology. Write your answer as an 
(x,y) point.

y=3x^(2)-12
Answer:

Find the coordinates of the vertex of the following parabola using graphing technology. Write your answer as an (x,y) (x, y) point.\newliney=3x212 y=3 x^{2}-12 \newlineAnswer:

Full solution

Q. Find the coordinates of the vertex of the following parabola using graphing technology. Write your answer as an (x,y) (x, y) point.\newliney=3x212 y=3 x^{2}-12 \newlineAnswer:
  1. Vertex Form Explanation: The vertex form of a parabola is y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola. To find the vertex of the parabola given by y=3x212y = 3x^2 - 12, we need to complete the square or use the vertex formula h=b2ah = -\frac{b}{2a} and k=cb24ak = c - \frac{b^2}{4a} for the standard form y=ax2+bx+cy = ax^2 + bx + c. In this case, a=3a = 3, b=0b = 0, and c=12c = -12. Since there is no bb term, the vertex will be at (h,k)(h, k)00. To find the (h,k)(h, k)11-coordinate of the vertex, we substitute (h,k)(h, k)22 into the equation y=3x212y = 3x^2 - 12.
  2. Calculate Vertex Coordinates: Substitute x=0x = 0 into the equation y=3x212y = 3x^2 - 12 to find the yy-coordinate of the vertex.\newliney=3(0)212y = 3(0)^2 - 12\newliney=012y = 0 - 12\newliney=12y = -12\newlineSo, the yy-coordinate of the vertex is 12-12.
  3. Final Vertex Coordinates: We have found the x-coordinate of the vertex to be 00 and the y-coordinate to be 12-12. Therefore, the coordinates of the vertex of the parabola y=3x212y = 3x^2 - 12 are (0,12)(0, -12).

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