Find the binomial that completes the factorization. y^3 - 64 = (______)(y^2 + 4y + 16)

Recognize difference of cubes: Recognize that y^3 - 64 is a difference of cubes since 64 is 4^3.Apply formula for factoring: Use the formula for factoring a difference of cubes: a^3 - b^3 = (a - b)(a^2 + ab + b^2).Identify values for a and b: Identify a = y and b = 4 to apply the formula.Plug values into formula: Plug a and b into the formula: y^3 - 64 = (y - 4)(y^2 + 4y + 16).

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Find the binomial that completes the factorization. $\newline$ $y^3 - 64 = (\underline{\hspace{3cm}})(y^2 + 4y + 16)$

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Algebra 2

Factor sums and differences of cubes

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Q. Find the binomial that completes the factorization.

\newline

y^3 - 64 = (\underline{\hspace{3cm}})(y^2 + 4y + 16)

Recognize difference of cubes: Recognize that $y^3 - 64$ is a difference of cubes since $64$ is $4^3$ .
Apply formula for factoring: Use the formula for factoring a difference of cubes: $a^3 - b^3 = (a - b)(a^2 + ab + b^2)$ .
Identify values for $a$ and $b$ : Identify $a = y$ and $b = 4$ to apply the formula.
Plug values into formula: Plug $a$ and $b$ into the formula: $y^3 - 64 = (y - 4)(y^2 + 4y + 16)$ .