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Let’s check out your problem:
Find the binomial that completes the factorization.
\newline
t
3
+
64
=
(
‾
)
(
t
2
−
4
t
+
16
)
t^3 + 64 = (\underline{\hspace{3cm}})(t^2 - 4t + 16)
t
3
+
64
=
(
)
(
t
2
−
4
t
+
16
)
View step-by-step help
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Math Problems
Algebra 2
Factor sums and differences of cubes
Full solution
Q.
Find the binomial that completes the factorization.
\newline
t
3
+
64
=
(
‾
)
(
t
2
−
4
t
+
16
)
t^3 + 64 = (\underline{\hspace{3cm}})(t^2 - 4t + 16)
t
3
+
64
=
(
)
(
t
2
−
4
t
+
16
)
Recognize formula:
Recognize the sum of cubes formula:
a
3
+
b
3
=
(
a
+
b
)
(
a
2
−
a
b
+
b
2
)
a^3 + b^3 = (a + b)(a^2 - ab + b^2)
a
3
+
b
3
=
(
a
+
b
)
(
a
2
−
ab
+
b
2
)
.
\newline
Here,
t
3
+
64
t^3 + 64
t
3
+
64
can be written as
t
3
+
4
3
t^3 + 4^3
t
3
+
4
3
.
Identify
a
a
a
and
b
b
b
:
Identify
a
a
a
and
b
b
b
from the sum of cubes formula.
a
=
t
a = t
a
=
t
and
b
=
4
b = 4
b
=
4
.
Apply formula:
Apply the sum of cubes formula:
t
3
+
4
3
=
(
t
+
4
)
(
t
2
−
t
⋅
4
+
4
2
)
t^3 + 4^3 = (t + 4)(t^2 - t\cdot 4 + 4^2)
t
3
+
4
3
=
(
t
+
4
)
(
t
2
−
t
⋅
4
+
4
2
)
.
Simplify expression:
Simplify the binomial and trinomial:
(
t
+
4
)
(
t
2
−
4
t
+
16
)
(t + 4)(t^2 - 4t + 16)
(
t
+
4
)
(
t
2
−
4
t
+
16
)
.
More problems from Factor sums and differences of cubes
Question
Factor out the greatest common factor. If the greatest common factor is
1
1
1
, just retype the polynomial.
\newline
4
x
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−
6
x
2
4x^3 - 6x^2
4
x
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−
6
x
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\newline
______
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Factor
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x
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x
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+
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completely.
\newline
All factors in your answer should have integer coefficients.
\newline
______
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Posted 9 months ago
Question
Find the binomial that completes the factorization.
\newline
t
3
+
u
3
=
(
‾
)
(
t
2
−
t
u
+
u
2
)
t^3 + u^3 = (\underline{\hspace{1cm}}) (t^2 - tu + u^2)
t
3
+
u
3
=
(
)
(
t
2
−
t
u
+
u
2
)
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\newline
g
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g
2
−
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g
+
18
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Question
Factor.
\newline
2
y
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−
y
2
+
16
y
−
8
2y^3 - y^2 + 16y - 8
2
y
3
−
y
2
+
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y
−
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\newline
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\newline
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Question
Factor.
\newline
2
x
8
+
7
x
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2x^8 + 7x^2
2
x
8
+
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x
2
\newline
______
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Question
Factor.
\newline
9
y
12
+
4
y
5
−
y
2
9y^{12} + 4y^5 - y^2
9
y
12
+
4
y
5
−
y
2
\newline
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Posted 9 months ago
Question
Factor.
\newline
6
a
4
+
3
a
3
−
a
+
2
6a^4 + 3a^3 - a + 2
6
a
4
+
3
a
3
−
a
+
2
\newline
_____
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Question
Factor.
\newline
4
c
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−
2
c
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+
c
2
−
5
4c^7 - 2c^5 + c^2 - 5
4
c
7
−
2
c
5
+
c
2
−
5
\newline
_____
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Question
Factor.
\newline
7
m
9
+
2
m
6
−
m
3
+
4
m
−
10
7m^9 + 2m^6 - m^3 + 4m - 10
7
m
9
+
2
m
6
−
m
3
+
4
m
−
10
\newline
_____
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Posted 9 months ago
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