Find the area of a rectangle with a length of 5(1)/(3) inches and a width of (2)/(3) inches. (A) (9)/(16)ln^(2) (B) (16)/(9)in^(2) (C) (32)/(9)in^(2) (D) (5)/(2)in^(2)

Convert to Improper Fraction: Convert the mixed number for the length to an improper fraction. The length of the rectangle is 5(1)/(3) inches, which can be converted to an improper fraction by multiplying the whole number by the denominator and adding the numerator, then placing the result over the original denominator. 5(1)/(3) = (5 * 3 + 1)/3 = (15 + 1)/3 = 16/3 inches.Identify Rectangle Width: Identify the width of the rectangle. The width of the rectangle is given as (2)/(3) inch, which is already in fraction form.Calculate Area: Calculate the area of the rectangle. The area of a rectangle is found by multiplying the length by the width. Area = (length) * (width) = (16/3) * (2/3) inches^2.Perform Multiplication: Perform the multiplication to find the area. Area = (16/3) * (2/3) = (16 * 2) / (3 * 3) = 32/9 inches^2.

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Find the area of a rectangle with a length of 5(1)/(3) inches and a width of (2)/(3) inches.
(A) (9)/(16)ln^(2)
(B) (16)/(9)in^(2)
(C) (32)/(9)in^(2)
(D) (5)/(2)in^(2)

Find the area of a rectangle with a length of $5 \frac{1}{3}$ inches and a width of $\frac{2}{3}$ inches $\newline$ (A) $\frac{9}{16} \mathrm{in}^{2}$ $\newline$ (B) $\frac{16}{9} \mathrm{in}^{2}$ $\newline$ (C) $\frac{32}{9} \mathrm{in}^{2}$ $\newline$ (D) $\frac{5}{2} \mathrm{in}^{2}$

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Math Problems

Algebra 2

Sum of finite series not start from 1

Full solution

Q. Find the area of a rectangle with a length of

5 \frac{1}{3}

inches and a width of

\frac{2}{3}

inches

\newline

(A)

\frac{9}{16} \mathrm{in}^{2}

\newline

(B)

\frac{16}{9} \mathrm{in}^{2}

\newline

(C)

\frac{32}{9} \mathrm{in}^{2}

\newline

(D)

\frac{5}{2} \mathrm{in}^{2}

Convert to Improper Fraction: Convert the mixed number for the length to an improper fraction. $\newline$ The length of the rectangle is $5\frac{1}{3}$ inches, which can be converted to an improper fraction by multiplying the whole number by the denominator and adding the numerator, then placing the result over the original denominator. $\newline$ $5\frac{1}{3} = \left(5 \times 3 + 1\right)/3 = \left(15 + 1\right)/3 = \frac{16}{3}$ inches.
Identify Rectangle Width: Identify the width of the rectangle. $\newline$ The width of the rectangle is given as $\frac{2}{3}$ inch, which is already in fraction form.
Calculate Area: Calculate the area of the rectangle. $\newline$ The area of a rectangle is found by multiplying the length by the width. $\newline$ Area = $(\text{length}) \times (\text{width}) = \left(\frac{16}{3}\right) \times \left(\frac{2}{3}\right)$ inches $^2$ .
Perform Multiplication: Perform the multiplication to find the area. $\newline$ Area = $(\frac{16}{3}) \times (\frac{2}{3}) = (\frac{16 \times 2}{3 \times 3}) = \frac{32}{9}$ inches $^2$ .