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Find the 9^th term of the geometric sequence 
2,8,32,dots
Answer:

Find the 9th 9^{\text {th }} term of the geometric sequence 2,8,32, 2,8,32, \ldots \newlineAnswer:

Full solution

Q. Find the 9th 9^{\text {th }} term of the geometric sequence 2,8,32, 2,8,32, \ldots \newlineAnswer:
  1. Identify Sequence Type: Identify the type of sequence. The given sequence is geometric because each term after the first is found by multiplying the previous term by a constant.
  2. Determine Common Ratio: Determine the common ratio rr of the sequence.\newlineThe second term is 88 and the first term is 22, so the common ratio is 82=4\frac{8}{2} = 4.
  3. Use Formula for nth Term: Use the formula for the nth term of a geometric sequence.\newlineThe nth term ana_n is given by an=a1r(n1)a_n = a_1 \cdot r^{(n-1)}, where a1a_1 is the first term and rr is the common ratio.
  4. Calculate 99th Term: Calculate the 99th term using the formula.\newlineThe first term a1a_1 is 22, the common ratio rr is 44, and nn is 99.\newlinea9=2×491=2×48a_9 = 2 \times 4^{9-1} = 2 \times 4^8
  5. Compute Power of 44: Compute the power of 44.\newline48=4×4×4×4×4×4×4×4=655364^8 = 4 \times 4 \times 4 \times 4 \times 4 \times 4 \times 4 \times 4 = 65536
  6. Multiply First Term: Multiply the first term by the result from the previous step. a9=2×65536=131072a_9 = 2 \times 65536 = 131072

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