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Find the 9^th term of the geometric sequence 
1,-4,16,dots
Answer:

Find the 9th 9^{\text {th }} term of the geometric sequence 1,4,16, 1,-4,16, \ldots \newlineAnswer:

Full solution

Q. Find the 9th 9^{\text {th }} term of the geometric sequence 1,4,16, 1,-4,16, \ldots \newlineAnswer:
  1. Identify Common Ratio: To find the 9th9^{\text{th}} term of a geometric sequence, we need to identify the common ratio (rr) of the sequence. The common ratio is found by dividing any term by the previous term.\newlineCalculation: r=(4)/1=4r = (-4) / 1 = -4
  2. Use Formula for nth Term: Now that we have the common ratio, we can use the formula for the nth term of a geometric sequence, which is an=a1×r(n1)a_n = a_1 \times r^{(n-1)}, where a1a_1 is the first term and nn is the term number.
  3. Calculate for 99th Term: We are looking for the 99th term n=9n=9, and we know the first term a1a_1 is 11, and the common ratio rr is 4-4.\newlineCalculation: a9=1×(4)91=1×(4)8a_9 = 1 \times (-4)^{9-1} = 1 \times (-4)^8
  4. Calculate (4)8(-4)^8: Now we calculate (4)8(-4)^8. Since 4-4 is raised to an even power, the result will be positive.\newlineCalculation: (4)8=65536(-4)^8 = 65536
  5. Multiply First Term: Finally, we multiply the first term by the result of (4)8(-4)^8 to find the 99th term.\newlineCalculation: a9=1×65536=65536a_9 = 1 \times 65536 = 65536

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