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Find the 8th term of the geometric sequence shown below.

-2x^(8),-4x^(10),-8x^(12),dots
Answer:

Find the 88th term of the geometric sequence shown below.\newline2x8,4x10,8x12, -2 x^{8},-4 x^{10},-8 x^{12}, \ldots \newlineAnswer:

Full solution

Q. Find the 88th term of the geometric sequence shown below.\newline2x8,4x10,8x12, -2 x^{8},-4 x^{10},-8 x^{12}, \ldots \newlineAnswer:
  1. Identify common ratio: Identify the common ratio rr of the geometric sequence by dividing the second term by the first term.\newlineCalculation: r=4x102x8r = \frac{-4x^{10}}{-2x^{8}}\newlineSimplification: r=2x2r = 2x^{2}
  2. Use nth term formula: Use the formula for the nth term of a geometric sequence, which is an=a1r(n1)a_n = a_1 \cdot r^{(n-1)}, where a1a_1 is the first term and nn is the term number.\newlineCalculation: a8=(2x8)(2x2)81a_8 = (-2x^{8}) \cdot (2x^{2})^{8-1}\newlineSimplification: a8=(2x8)(2x2)7a_8 = (-2x^{8}) \cdot (2x^{2})^7
  3. Simplify 88th term: Simplify the expression for the 88th term by calculating the exponent and multiplication.\newlineCalculation: a8=(2x8)×(128x14)a_8 = (-2x^{8}) \times (128x^{14})\newlineSimplification: a8=256x22a_8 = -256x^{22}

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