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Find the 8th term of the geometric sequence shown below.

-2x^(3),4x^(6),-8x^(9),dots
Answer:

Find the 88th term of the geometric sequence shown below.\newline2x3,4x6,8x9, -2 x^{3}, 4 x^{6},-8 x^{9}, \ldots \newlineAnswer:

Full solution

Q. Find the 88th term of the geometric sequence shown below.\newline2x3,4x6,8x9, -2 x^{3}, 4 x^{6},-8 x^{9}, \ldots \newlineAnswer:
  1. Identify Common Ratio: To find the 8th8^{th} term of a geometric sequence, we need to identify the common ratio (r)(r) and use the formula for the nthn^{th} term of a geometric sequence, which is an=a1r(n1)a_n = a_1 \cdot r^{(n-1)}, where a1a_1 is the first term and nn is the term number.
  2. Calculate Common Ratio: First, let's find the common ratio by dividing the second term by the first term. \newliner=4x62x3=2x63=2x3r = \frac{4x^{6}}{-2x^{3}} = -2x^{6-3} = -2x^{3}
  3. Find 8th8^{\text{th}} Term: Now that we have the common ratio, we can use it to find the 8th8^{\text{th}} term.a8=a1×r(81)=a1×r7a_8 = a_1 \times r^{(8-1)} = a_1 \times r^7
  4. Substitute Values: Substitute the values we know into the formula.\newlinea8=(2x3)(2x3)7a_8 = (-2x^{3}) \cdot (-2x^{3})^7
  5. Simplify Expression: Simplify the expression by calculating the exponent and the multiplication. a8=(2x3)×(128x21)=256x24a_8 = (-2x^{3}) \times (128x^{21}) = -256x^{24}

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