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Find the 81 st term of the arithmetic sequence 
24,11,-2,dots
Answer:

Find the 8181 st term of the arithmetic sequence 24,11,2, 24,11,-2, \ldots \newlineAnswer:

Full solution

Q. Find the 8181 st term of the arithmetic sequence 24,11,2, 24,11,-2, \ldots \newlineAnswer:
  1. Identify first term: To find the 81st81^{st} term of an arithmetic sequence, we need to use the formula for the nthn^{th} term of an arithmetic sequence, which is an=a1+(n1)da_n = a_1 + (n - 1)d, where ana_n is the nthn^{th} term, a1a_1 is the first term, nn is the term number, and dd is the common difference between the terms.
  2. Find common difference: First, we identify the first term a1a_1 of the sequence, which is given as 2424.
  3. Calculate 81st81^{st} term: Next, we need to find the common difference (d)(d). We can do this by subtracting the second term from the first term: d=1124=13d = 11 - 24 = -13.
  4. Substitute values: Now that we have the first term and the common difference, we can find the 81st81^{\text{st}} term (a81a_{81}) using the formula: a81=a1+(811)da_{81} = a_1 + (81 - 1)d.
  5. Perform calculation: Substitute the known values into the formula: a81=24+(811)(13)a_{81} = 24 + (81 - 1)(-13).
  6. Multiply common difference: Perform the calculation inside the parentheses: 811=8081 - 1 = 80.
  7. Add to first term: Now multiply the common difference by 8080: 80×(13)=104080 \times (-13) = -1040.
  8. Add to first term: Now multiply the common difference by 8080: 80×(13)=104080 \times (-13) = -1040.Finally, add this result to the first term: a81=24+(1040)=1016a_{81} = 24 + (-1040) = -1016.

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