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Find the 7th term of the geometric sequence shown below.

-6x^(7),30x^(8),-150x^(9),dots
Answer:

Find the 77th term of the geometric sequence shown below.\newline6x7,30x8,150x9, -6 x^{7}, 30 x^{8},-150 x^{9}, \ldots \newlineAnswer:

Full solution

Q. Find the 77th term of the geometric sequence shown below.\newline6x7,30x8,150x9, -6 x^{7}, 30 x^{8},-150 x^{9}, \ldots \newlineAnswer:
  1. Identify first term and ratio: To find the 7th7^{\text{th}} term of a geometric sequence, we need to identify the first term (a1a_1) and the common ratio (rr) of the sequence.\newlineThe first term (a1a_1) is given as 6x7-6x^{7}.
  2. Calculate common ratio: Next, we find the common ratio rr by dividing the second term by the first term.r=30x86x7r = \frac{30x^{8}}{-6x^{7}}r=5xr = -5x
  3. Use nth term formula: Now that we have the first term and the common ratio, we can use the formula for the nth term of a geometric sequence, which is an=a1×r(n1)a_n = a_1 \times r^{(n-1)}, where nn is the term number.\newlineWe want to find the 77th term, so n=7n = 7.
  4. Substitute values for 77th term: Substitute the values into the formula to find the 77th term. \newlinea7=(6x7)×(5x)71a_7 = (-6x^{7}) \times (-5x)^{7-1}\newlinea7=(6x7)×(5x)6a_7 = (-6x^{7}) \times (-5x)^{6}
  5. Simplify expression for 77th term: Simplify the expression to find the 77th term.\newlinea7=(6x7)×(15625x6)//(5)6=15625a_7 = (-6x^{7}) \times (15625x^{6}) // (-5)^6 = 15625\newlinea7=93750x13a_7 = -93750x^{13} // Multiply the coefficients and add the exponents for xx

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