Find the 73 rd term of the arithmetic sequence -28,-34,-40,dots Answer:

Identify pattern: Identify the pattern of the sequence to determine if it is arithmetic. The sequence is decreasing by 6 each time, which means it is an arithmetic sequence with a common difference (d) of -6.Find first term: Find the first term (a1) of the sequence. The first term of the sequence is given as -28.Use formula: Use the formula for the nth term of an arithmetic sequence: an = a1 + (n - 1)d. We need to find the 73rd term (a73), so n = 73, a1 = -28, and d = -6.Calculate 73rd term: Substitute the values into the formula and calculate the 73rd term. a73 = -28 + (73 - 1)(-6) a73 = -28 + (72)(-6) a73 = -28 - 432 a73 = -460

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Find the 73 rd term of the arithmetic sequence
-28,-34,-40,dots
Answer:

Find the $73$ rd term of the arithmetic sequence $-28,-34,-40, \ldots$ $\newline$ Answer:

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Algebra 1

Write variable expressions for geometric sequences

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Q. Find the

73

rd term of the arithmetic sequence

-28,-34,-40, \ldots

\newline

Answer:

Identify pattern: Identify the pattern of the sequence to determine if it is arithmetic. $\newline$ The sequence is decreasing by $6$ each time, which means it is an arithmetic sequence with a common difference ( $d$ ) of $-6$ .
Find first term: Find the first term $a_1$ of the sequence. $\newline$ The first term of the sequence is given as $-28$ .
Use formula: Use the formula for the $n$ th term of an arithmetic sequence: $a_n = a_1 + (n - 1)d$ . We need to find the $73$ rd term ( $a_{73}$ ), so $n = 73$ , $a_1 = -28$ , and $d = -6$ .
Calculate $73$ rd term: Substitute the values into the formula and calculate the $73^{rd}$ term. $\newline$ $a_{73} = -28 + (73 - 1)(-6)$ $\newline$ $a_{73} = -28 + (72)(-6)$ $\newline$ $a_{73} = -28 - 432$ $\newline$ $a_{73} = -460$