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Find the 56 th term of the arithmetic sequence 
-14,-26,-38,dots
Answer:

Find the 5656 th term of the arithmetic sequence 14,26,38, -14,-26,-38, \ldots \newlineAnswer:

Full solution

Q. Find the 5656 th term of the arithmetic sequence 14,26,38, -14,-26,-38, \ldots \newlineAnswer:
  1. Identify First Term: To find the 56th56^{th} term of an arithmetic sequence, we need to use the formula for the nthn^{th} term of an arithmetic sequence, which is an=a1+(n1)da_n = a_1 + (n - 1)d, where ana_n is the nthn^{th} term, a1a_1 is the first term, nn is the term number, and dd is the common difference between the terms.
  2. Find Common Difference: First, we identify the first term a1a_1 of the sequence, which is 14-14.
  3. Calculate 56th56^{th} Term: Next, we need to find the common difference (d)(d). We can do this by subtracting the first term from the second term: 26(14)=26+14=12-26 - (-14) = -26 + 14 = -12.
  4. Substitute Values: Now that we have the first term and the common difference, we can find the 56th56^{\text{th}} term (a56a_{56}) using the formula: a56=a1+(561)da_{56} = a_1 + (56 - 1)d.
  5. Perform Calculation: Substitute the known values into the formula: a56=14+(561)(12)a_{56} = -14 + (56 - 1)(-12).
  6. Multiply and Add: Perform the calculation inside the parentheses first: 561=5556 - 1 = 55.
  7. Multiply and Add: Perform the calculation inside the parentheses first: 561=5556 - 1 = 55.Now multiply 5555 by the common difference, 12-12: 55×12=66055 \times -12 = -660.
  8. Multiply and Add: Perform the calculation inside the parentheses first: 561=5556 - 1 = 55.Now multiply 5555 by the common difference, 12-12: 55×12=66055 \times -12 = -660.Finally, add the first term to this product to find the 5656th term: a56=14+(660)=674a_{56} = -14 + (-660) = -674.

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