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Find the 3 rd term in the expansion of 
(3x-2)^(4) in simplest form.
Answer:

Find the 33 rd term in the expansion of (3x2)4 (3 x-2)^{4} in simplest form.\newlineAnswer:

Full solution

Q. Find the 33 rd term in the expansion of (3x2)4 (3 x-2)^{4} in simplest form.\newlineAnswer:
  1. Use Binomial Theorem: To find the 33rd term in the expansion of (3x2)4(3x-2)^{4}, we will use the binomial theorem. The binomial theorem states that the nnth term in the expansion of (a+b)m(a+b)^{m} is given by the formula: T(n)=C(m,n1)a(mn+1)b(n1)T(n) = C(m, n-1) \cdot a^{(m-n+1)} \cdot b^{(n-1)}, where C(m,n1)C(m, n-1) is the binomial coefficient. For the 33rd term, n=3n=3.
  2. Calculate Binomial Coefficient: First, we calculate the binomial coefficient for the 33rd term, which is C(4,31)C(4, 3-1) or C(4,2)C(4, 2). The binomial coefficient C(4,2)C(4, 2) is calculated as 4!2!(42)!\frac{4!}{2! \cdot (4-2)!}, which simplifies to 4321=6\frac{4\cdot3}{2\cdot1} = 6.
  3. Calculate Powers of a and b: Next, we calculate the powers of aa and bb for the 33rd term. Since aa is 3x3x and bb is 2-2, and we are looking for the 33rd term (n=3n=3), we have a43+1=(3x)2a^{4-3+1} = (3x)^{2} and bb00.
  4. Multiply Coefficient and Powers: Now we multiply the binomial coefficient by the powers of aa and bb. So the 33rd term is 6×(3x)2×(2)16 \times (3x)^{2} \times (-2)^{1}. This simplifies to 6×9x2×26 \times 9x^2 \times -2, which is 108x2-108x^2.
  5. Final Result: Therefore, the 3rd3^{\text{rd}} term in the expansion of (3x2)4(3x-2)^{4} in simplest form is 108x2-108x^2.

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