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Find the 2 nd term in the expansion of 
(4x-1)^(6) in simplest form.
Answer:

Find the 22 nd term in the expansion of (4x1)6 (4 x-1)^{6} in simplest form.\newlineAnswer:

Full solution

Q. Find the 22 nd term in the expansion of (4x1)6 (4 x-1)^{6} in simplest form.\newlineAnswer:
  1. Use Binomial Theorem: To find the 22nd term in the expansion of (4x1)6(4x-1)^{6}, we will use the binomial theorem. The general form of the kk-th term in the expansion of (a+b)n(a+b)^{n} is given by T(k)=(nk1)ank+1bk1T(k) = \binom{n}{k-1} \cdot a^{n-k+1} \cdot b^{k-1}, where (nk1)\binom{n}{k-1} is the binomial coefficient. For the 22nd term, k=2k=2.
  2. Calculate Binomial Coefficient: First, we calculate the binomial coefficient for the 22nd term, which is 6C16C1 (since k1=21=1k-1 = 2-1 = 1). 6C16C1 is the number of combinations of 66 items taken 11 at a time, which is simply 66.
  3. Raise First Term to Power: Next, we raise the first term of the binomial, 4x4x, to the power of (62+1)(6-2+1) which is 55. So, (4x)5=45×x5=1024x5(4x)^5 = 4^5 \times x^5 = 1024x^5.
  4. Raise Second Term to Power: Then, we raise the second term of the binomial, 1-1, to the power of (21)(2-1) which is 11. So, (1)1=1(-1)^1 = -1.
  5. Multiply Coefficient and Terms: Now, we multiply the binomial coefficient by the powers of the first and second terms. The 22nd term of the expansion is 6×1024x5×(1)=6144x56 \times 1024x^5 \times (-1) = -6144x^5.
  6. Simplify the Expression: Finally, we simplify the expression to get the 22nd term in its simplest form. The 22nd term is 6144x5-6144x^5.

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