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Find the 
15^("th ") term of the arithmetic sequence 
5x+1,9x+7,13 x+13,dots
Answer:

Find the 15th  15^{\text {th }} term of the arithmetic sequence 5x+1,9x+7,13x+13, 5 x+1,9 x+7,13 x+13, \ldots \newlineAnswer:

Full solution

Q. Find the 15th  15^{\text {th }} term of the arithmetic sequence 5x+1,9x+7,13x+13, 5 x+1,9 x+7,13 x+13, \ldots \newlineAnswer:
  1. Determine Common Difference: To find the 15th15^{th} term of an arithmetic sequence, we need to determine the common difference between consecutive terms and then use the formula for the nthn^{th} term of an arithmetic sequence, which is an=a1+(n1)da_n = a_1 + (n - 1)d, where ana_n is the nthn^{th} term, a1a_1 is the first term, and dd is the common difference.
  2. Find Common Difference: First, let's find the common difference dd by subtracting the first term from the second term: (9x+7)(5x+1)=4x+6(9x + 7) - (5x + 1) = 4x + 6. Then, subtract the second term from the third term: (13x+13)(9x+7)=4x+6(13x + 13) - (9x + 7) = 4x + 6. Since the difference is the same, the common difference dd is 4x+64x + 6.
  3. Use Formula for 1515th Term: Now, we can use the formula to find the 1515th term a15a_{15}. The first term a1a_1 is 5x+15x + 1. Plugging the values into the formula, we get a15=(5x+1)+(151)(4x+6)a_{15} = (5x + 1) + (15 - 1)(4x + 6).
  4. Simplify Expression: Simplify the expression: $a_{\(15\)} = (\(5\)x + \(1\)) + \(14\)(\(4\)x + \(6\)) = (\(5\)x + \(1\)) + (\(56\)x + \(84\)) = \(61\)x + \(85\).

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