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Find the 
14^("th ") term of the geometric sequence 
5,10,20,dots
Answer:

Find the 14th  14^{\text {th }} term of the geometric sequence 5,10,20, 5,10,20, \ldots \newlineAnswer:

Full solution

Q. Find the 14th  14^{\text {th }} term of the geometric sequence 5,10,20, 5,10,20, \ldots \newlineAnswer:
  1. Identify first term: To find the 14th14^{th} term of a geometric sequence, we need to use the formula for the nthn^{th} term of a geometric sequence, which is an=a1×r(n1)a_n = a_1 \times r^{(n-1)}, where a1a_1 is the first term, rr is the common ratio, and nn is the term number.
  2. Find common ratio: First, we identify the first term a1a_1 of the sequence, which is 55.
  3. Calculate 1414th term: Next, we need to find the common ratio rr. We can do this by dividing the second term by the first term, or the third term by the second term. Let's use the second term divided by the first term: r=105=2r = \frac{10}{5} = 2.
  4. Calculate 2132^{13}: Now that we have the first term and the common ratio, we can find the 14th14^{th} term (a14a_{14}) using the formula: a14=5×2141=5×213a_{14} = 5 \times 2^{14-1} = 5 \times 2^{13}.
  5. Multiply to get 1414th term: Calculating 2132^{13}: 213=81922^{13} = 8192.
  6. Multiply to get 1414th term: Calculating 2132^{13}: 213=81922^{13} = 8192. Now, we multiply the first term by 2132^{13} to get the 1414th term: a14=5×8192=40960a_{14} = 5 \times 8192 = 40960.

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