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Find the 14 th term of the arithmetic sequence 
-5x+1,-12 x-3,-19 x-7,dots
Answer:

Find the 1414 th term of the arithmetic sequence 5x+1,12x3,19x7, -5 x+1,-12 x-3,-19 x-7, \ldots \newlineAnswer:

Full solution

Q. Find the 1414 th term of the arithmetic sequence 5x+1,12x3,19x7, -5 x+1,-12 x-3,-19 x-7, \ldots \newlineAnswer:
  1. Find Common Difference: To find the 14th14^{\text{th}} term of an arithmetic sequence, we need to determine the common difference between consecutive terms and then use the formula for the nthn^{\text{th}} term of an arithmetic sequence, which is an=a1+(n1)da_n = a_1 + (n - 1)d, where ana_n is the nthn^{\text{th}} term, a1a_1 is the first term, nn is the term number, and dd is the common difference.\newlineFirst, let's find the common difference (d)(d) by subtracting the first term from the second term.\newlined=(12x3)(5x+1)d = (-12x - 3) - (-5x + 1)\newlinenthn^{\text{th}}00\newlinenthn^{\text{th}}11
  2. Calculate 1414th Term: Now that we have the common difference, we can use the formula to find the 1414th term a14a_{14}.a14=a1+(141)(7x4)a_{14} = a_1 + (14 - 1)(-7x - 4)a14=(5x+1)+13(7x4)a_{14} = (-5x + 1) + 13(-7x - 4)
  3. Simplify Expression: Next, we will simplify the expression to find a14a_{14}. \newlinea14=(5x+1)+(91x52)a_{14} = (-5x + 1) + (-91x - 52)\newlinea14=5x+191x52a_{14} = -5x + 1 - 91x - 52\newlinea14=96x51a_{14} = -96x - 51

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