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Find the 
13^("th ") term of the geometric sequence 
8,16,32,dots
Answer:

Find the 13th  13^{\text {th }} term of the geometric sequence 8,16,32, 8,16,32, \ldots \newlineAnswer:

Full solution

Q. Find the 13th  13^{\text {th }} term of the geometric sequence 8,16,32, 8,16,32, \ldots \newlineAnswer:
  1. Identify first term: To find the 13th13^{\text{th}} term of a geometric sequence, we need to use the formula for the nthn^{\text{th}} term of a geometric sequence, which is an=a1r(n1)a_n = a_1 \cdot r^{(n-1)}, where a1a_1 is the first term, rr is the common ratio, and nn is the term number we want to find.
  2. Find common ratio: First, we identify the first term a1a_1 of the sequence, which is 88.
  3. Calculate 1313th term: Next, we need to find the common ratio rr. We can do this by dividing the second term by the first term: r=168=2r = \frac{16}{8} = 2.
  4. Calculate exponent: Now that we have the first term and the common ratio, we can find the 13th13^{\text{th}} term (a13a_{13}) using the formula: a13=8×2(131)a_{13} = 8 \times 2^{(13-1)}.
  5. Calculate 2122^{12}: We calculate the exponent: 2131=2122^{13-1} = 2^{12}.
  6. Multiply first term: Next, we calculate 2122^{12}, which is 40964096.
  7. Multiply first term: Next, we calculate 2122^{12}, which is 40964096.Finally, we multiply the first term by 40964096 to find the 1313th term: a13=8×4096=32768a_{13} = 8 \times 4096 = 32768.

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