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Find the 12th term of the geometric sequence shown below.

-8x^(2),16x^(5),-32x^(8),dots
Answer:

Find the 1212th term of the geometric sequence shown below.\newline8x2,16x5,32x8, -8 x^{2}, 16 x^{5},-32 x^{8}, \ldots \newlineAnswer:

Full solution

Q. Find the 1212th term of the geometric sequence shown below.\newline8x2,16x5,32x8, -8 x^{2}, 16 x^{5},-32 x^{8}, \ldots \newlineAnswer:
  1. Identify Common Ratio: To find the 12th12^{th} term of a geometric sequence, we need to identify the common ratio (rr) of the sequence. The common ratio is found by dividing any term by the previous term.
  2. Calculate Common Ratio: Let's find the common ratio by dividing the second term by the first term: r=16x58x2=2x3r = \frac{16x^5}{-8x^2} = -2x^3
  3. Use Formula for nth Term: Now that we have the common ratio, we can use the formula for the nth term of a geometric sequence, which is an=a1×r(n1)a_n = a_1 \times r^{(n-1)}, where a1a_1 is the first term and nn is the term number.
  4. Find 1212th Term: We want to find the 1212th term a12a_{12}. We already know the first term a1a_1 is 8x2-8x^2 and the common ratio rr is 2x3-2x^3. Plugging these values into the formula gives us:\newlinea12=a1r121=8x2(2x3)11a_{12} = a_1 \cdot r^{12-1} = -8x^2 \cdot (-2x^3)^{11}
  5. Calculate Exponent: Now we need to calculate (2x3)11(-2x^3)^{11}. When raising a power to a power, we multiply the exponents: (2x3)11=(2)11×(x3)11=2048x33(-2x^3)^{11} = (-2)^{11} \times (x^3)^{11} = -2048x^{33}
  6. Multiply to Find 1212th Term: Finally, we multiply the first term by this value to find the 1212th term: a12=8x2×2048x33=16384x35a_{12} = -8x^2 \times -2048x^{33} = 16384x^{35}

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