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Find the 12th term of the geometric sequence shown below.

6x^(6),-30x^(11),150x^(16),dots
Answer:

Find the 1212th term of the geometric sequence shown below.\newline6x6,30x11,150x16, 6 x^{6},-30 x^{11}, 150 x^{16}, \ldots \newlineAnswer:

Full solution

Q. Find the 1212th term of the geometric sequence shown below.\newline6x6,30x11,150x16, 6 x^{6},-30 x^{11}, 150 x^{16}, \ldots \newlineAnswer:
  1. Find Common Ratio: To find the 12th12^{\text{th}} term of a geometric sequence, we need to identify the common ratio (rr) between consecutive terms. We can find the common ratio by dividing the second term by the first term.\newlineCalculation:\newliner=30x116x6r = \frac{-30x^{11}}{6x^{6}}\newliner=5x116r = -5x^{11-6}\newliner=5x5r = -5x^5
  2. Calculate 1212th Term: Now that we have the common ratio, we can find the 1212th term a12a_{12} using the formula for the nth term of a geometric sequence, which is an=a1r(n1)a_n = a_1 \cdot r^{(n-1)}, where a1a_1 is the first term and nn is the term number.\newlineCalculation:\newlinea12=6x6(5x5)121a_{12} = 6x^{6} \cdot (-5x^5)^{12-1}\newlinea12=6x6(5x5)11a_{12} = 6x^{6} \cdot (-5x^5)^{11}
  3. Simplify Expression: We need to simplify the expression for a12a_{12} by performing the exponentiation and multiplication.\newlineCalculation:\newlinea12=6x6×(5)11×x5×11a_{12} = 6x^{6} \times (-5)^{11} \times x^{5\times11}\newlinea12=6x6×(5)11×x55a_{12} = 6x^{6} \times (-5)^{11} \times x^{55}\newlinea12=6×(5)11×x6+55a_{12} = 6 \times (-5)^{11} \times x^{6+55}\newlinea12=6×(5)11×x61a_{12} = 6 \times (-5)^{11} \times x^{61}
  4. Calculate Value: Finally, we calculate the value of (5)11(-5)^{11} to find the 1212th term.\newlineCalculation:\newline(5)11=5×5×5×5×5×5×5×5×5×5×5(-5)^{11} = -5 \times -5 \times -5 \times -5 \times -5 \times -5 \times -5 \times -5 \times -5 \times -5 \times -5\newline(5)11=48828125(-5)^{11} = -48828125\newlinea12=6×(48828125)×x61a_{12} = 6 \times (-48828125) \times x^{61}\newlinea12=292968750×x61a_{12} = -292968750 \times x^{61}

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