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Find the 11th term of the arithmetic sequence 
x+1,-5x+7,-11 x+13,dots
Answer:

Find the 1111th term of the arithmetic sequence x+1,5x+7,11x+13, x+1,-5 x+7,-11 x+13, \ldots \newlineAnswer:

Full solution

Q. Find the 1111th term of the arithmetic sequence x+1,5x+7,11x+13, x+1,-5 x+7,-11 x+13, \ldots \newlineAnswer:
  1. Determine common difference: To find the 11th11^{\text{th}} term of an arithmetic sequence, we need to determine the common difference between consecutive terms and then use the formula for the nthn^{\text{th}} term of an arithmetic sequence, which is an=a1+(n1)da_n = a_1 + (n - 1)d, where ana_n is the nthn^{\text{th}} term, a1a_1 is the first term, nn is the term number, and dd is the common difference.
  2. Find common difference: First, let's find the common difference dd by subtracting the first term from the second term.d=(5x+7)(x+1)=5x+7x1=6x+6d = (-5x + 7) - (x + 1) = -5x + 7 - x - 1 = -6x + 6
  3. Verify common difference: Now, let's verify the common difference by subtracting the second term from the third term. \newlined=(11x+13)(5x+7)=11x+13+5x7=6x+6d = (-11x + 13) - (-5x + 7) = -11x + 13 + 5x - 7 = -6x + 6\newlineThis confirms that the common difference is indeed 6x+6-6x + 6.
  4. Find 1111th term: Using the formula for the nth term, we can now find the 1111th term a11a_{11}.a11=a1+(111)(6x+6)=(x+1)+10(6x+6)a_{11} = a_1 + (11 - 1)(-6x + 6) = (x + 1) + 10(-6x + 6)
  5. Simplify expression: Simplify the expression to find the 11th11^{\text{th}} term.a11=x+1+10(6x)+10(6)=x+160x+60a_{11} = x + 1 + 10(-6x) + 10(6) = x + 1 - 60x + 60
  6. Combine like terms: Combine like terms to get the final expression for the 11th11^{th} term.a11=59x+61a_{11} = -59x + 61

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