Find tan(12π) exactly using an angle addition or subtraction formula.[Hint: This diagram of special trigonometry. values may help].Choose 1 answer:(A) 3+33−3(B) 3−3−3−3(C) 3−33+3(D) 3+3−3+3
Q. Find tan(12π) exactly using an angle addition or subtraction formula.[Hint: This diagram of special trigonometry. values may help].Choose 1 answer:(A) 3+33−3(B) 3−3−3−3(C) 3−33+3(D) 3+3−3+3
Recognize the angle: Recognize that (π)/12 is not a standard angle for which we have a direct trigonometric value. However, we can express (π)/12 as the difference of two angles whose tangent values we know: (π)/12=(π)/4−(π)/6.
Use the tangent subtraction formula: Use the tangent subtraction formula: tan(A−B)=1+tan(A)tan(B)tan(A)−tan(B). Here, A=4π and B=6π.
Find tangent values: Find the tangent values for A and B. We know that tan(4π)=1 and tan(6π)=33.
Substitute values into formula: Substitute the values into the tangent subtraction formula: tan(12π)=1+tan(4π)tan(6π)tan(4π)−tan(6π)=1+(1)(3/3)1−3/3.
Simplify the expression: Simplify the expression: tan(12π)=1+3/31−3/3=3+33−3.
Rationalize the denominator: Rationalize the denominator by multiplying the numerator and the denominator by the conjugate of the denominator: (3+33−3)⋅(3−33−3).
Simplify the expression: Simplify the expression: (12−63)/6=2−3.
Check the answer choices: Check the answer choices to see which one matches our result. The correct answer is (A) (3−3)/(3+3), which simplifies to 2−3 after rationalizing the denominator.