Find lim_(x rarr1)f(x) for f(x)=sqrt(51-2x)". "

Identify Function & Point: Identify the function and the point at which we need to find the limit. We have the function f(x) = sqrt(51 - 2x) and we need to find the limit as x approaches 1.Substitute Value & Check: Substitute the value of x into the function to see if the function is defined at that point. Let's substitute x = 1 into the function: f(1) = sqrt(51 - 2*1) = sqrt(49).Calculate Substitution Result: Calculate the value obtained after substitution. sqrt(49) = 7, so f(1) = 7.Check Direct Substitution: Determine if we can use direct substitution to find the limit. Since the function is defined at x = 1 and we obtained a real number after substitution, we can use direct substitution to find the limit.Conclude Limit: Conclude the limit based on the calculations. The limit of f(x) as x approaches 1 is equal to the value of the function at x = 1, which is 7.

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Find
lim_(x rarr1)f(x) for

f(x)=sqrt(51-2x)". "

Find $\lim _{x \rightarrow 1} f(x)$ for $\newline$ $f(x)=\sqrt{51-2 x} \text {. }$

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Algebra 1

Domain and range of square root functions: equations

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Q. Find

\lim _{x \rightarrow 1} f(x)

for

\newline

f(x)=\sqrt{51-2 x} \text {. }

Identify Function & Point: Identify the function and the point at which we need to find the limit. $\newline$ We have the function $f(x) = \sqrt{51 - 2x}$ and we need to find the limit as $x$ approaches $1$ .
Substitute Value & Check: Substitute the value of $x$ into the function to see if the function is defined at that point. $\newline$ Let's substitute $x = 1$ into the function: $f(1) = \sqrt{51 - 2 \times 1} = \sqrt{49}$ .
Calculate Substitution Result: Calculate the value obtained after substitution. $\sqrt{49} = 7$ , so $f(1) = 7$ .
Check Direct Substitution: Determine if we can use direct substitution to find the limit. Since the function is defined at $x = 1$ and we obtained a real number after substitution, we can use direct substitution to find the limit.
Conclude Limit: Conclude the limit based on the calculations. $\newline$ The limit of $f(x)$ as $x$ approaches $1$ is equal to the value of the function at $x = 1$ , which is $7$ .