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Let’s check out your problem:
Find each
square root
. Where necessary, round to the nearest
100
100
100
th:
\newline
2
72
\sqrt{\frac{2}{72}}
72
2
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Math Problems
Algebra 2
Roots of rational numbers
Full solution
Q.
Find each square root. Where necessary, round to the nearest
100
100
100
th:
\newline
2
72
\sqrt{\frac{2}{72}}
72
2
Simplify Fraction:
First, simplify the
fraction
under the square root.
\newline
(
2
72
)
=
(
1
36
)
(\frac{2}{72}) = (\frac{1}{36})
(
72
2
)
=
(
36
1
)
Find Square Root:
Now, find the square root of the simplified fraction.
1
36
=
1
36
\sqrt{\frac{1}{36}} = \frac{\sqrt{1}}{\sqrt{36}}
36
1
=
36
1
Calculate Square Roots:
Calculate the square roots of the numerator and the denominator.
\newline
1
=
1
\sqrt{1} = 1
1
=
1
\newline
36
=
6
\sqrt{36} = 6
36
=
6
Divide to Get Answer:
Divide the square roots to get the final answer.
1
6
=
0.1666
…
\frac{1}{6} = 0.1666\ldots
6
1
=
0.1666
…
Round to Nearest Hundredth:
Round the result to the nearest hundredth.
0.1666
…
≈
0.17
0.1666\ldots \approx 0.17
0.1666
…
≈
0.17
More problems from Roots of rational numbers
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\newline
16
\sqrt{16}
16
\newline
\newline
Write your answer in simplified form.
\newline
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\newline
9
16
\sqrt{\frac{9}{16}}
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Find the real-number root using a calculator. Round your answer to the nearest thousandth.
\newline
`\sqrt{957} `
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Multiply. Write your answer in simplest form.
\newline
273
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42
\sqrt{273} \times \sqrt{42}
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Question
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\newline
63
4
\sqrt{\frac{63}{4}}
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Question
Simplify. Rationalize the denominator.
\newline
−
4
9
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\frac{-4}{9 - \sqrt{2}}
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Question
Solve for
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z
z
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\newline
16
=
z
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16
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\newline
z
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Question
Simplify the radical expression.
14
x
14
\sqrt{14x^{14}}
14
x
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Write your answer in the form
A
A
A
,
B
\sqrt{B}
B
, or
A
B
A\sqrt{B}
A
B
, where
A
A
A
and
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B
B
are constants or expressions in
x
x
x
. Use at most one radical in your answer, and at most one absolute value symbol in your expression for
A
A
A
. ______
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Question
Simplify the radical expression.
\newline
12
x
12
\sqrt{12x^{12}}
12
x
12
\newline
Write your answer in the form
A
A
A
,
B
\sqrt{B}
B
, or
A
B
A\sqrt{B}
A
B
, where
A
A
A
and
B
B
B
are constants or expressions in
x
x
x
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A
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\newline
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\underline{\hspace{3cm}}
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Question
What is the value of
sin
(
5
π
6
)
?
\sin \left(\frac{5 \pi}{6}\right) ?
sin
(
6
5
π
)
?
\newline
Choose
1
1
1
answer:
\newline
(A)
−
3
2
-\frac{\sqrt{3}}{2}
−
2
3
\newline
(B)
−
2
2
-\frac{\sqrt{2}}{2}
−
2
2
\newline
(C)
1
2
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2
1
\newline
(D)
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